Design of Electrical Machines Mock Test 6

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Question 1 of 10

1. How does the portative electromagnet work as?

connecting magnet

repulsion magnets

holding magnet

attraction magnets

Question 1 of 10

Question 2 of 10

2. What type of gears are used in the small loads and low inertia motors?

worm gears

helical gears

worm gears and helical gears

spur gears

Question 2 of 10

Question 3 of 10

3. The peripheral speed is the armature peripheral speed in the stationary field coils.

true

false

Question 3 of 10

Question 4 of 10

4. How many design steps are present in the design of PMDC motors?

Question 4 of 10

Question 5 of 10

5. High value of the specific electric loading can be used for low voltage machines.

false

true

Question 5 of 10

Question 6 of 10

6. For good performance the small dc motor should have magnetic to electrical boarding ratio greater than 70.

false

true

Question 6 of 10

Question 7 of 10

7. Why are slot made deeper in the machine?

to increase the open circuit current

to increase the short circuit current

to reduce the short circuit current

to reduce the open circuit current

Question 7 of 10

Question 8 of 10

8. What is the relation of the force and the air gap length in the flat faced plunger type?

force is directly proportional to the air gap length

force is indirectly proportional to the air gap length

force is directly proportional to the square of the air gap length

force is indirectly proportional to the square of the air gap length

Question 8 of 10

Question 9 of 10

9. How many factors influence the choice of specific electric loading?

Question 9 of 10

Question 10 of 10

10. What is the formula for the total eddy current loss in conductors?

total copper loss = 3 / average value of the eddy current constant * current per phase² * dc resistance

total copper loss = 3 * average value of the eddy current constant / current per phase² * dc resistance

total copper loss = 3 * average value of the eddy current constant * current per phase² * dc resistance

total copper loss = 3 * average value of the eddy current constant * current per phase² / dc resistance

Question 10 of 10