C Array Test - 3 - Sanfoundry

1. What will be the output of the following C code?

    #include <stdio.h>
    void main()
    {
        char *a[10] = {"hi", "hello", "how"};
        int i = 0;
        for (i = 0;i < 10; i++)
        printf("%s", *(a[i]));
    }

hi hello how followed by 7 null values

10 null values

depends on compiler

segmentation fault

2. An array of strings can be initialized by _________

char *a[] = {"Hello", "Worlds"};

char *a[] = {"Hello", "World"};

all of the mentioned

char *b = "Hello";
char *c = "World";
char *a[] = {b, c};

3. What will be the output of the following C code?

    #include <stdio.h>
    int main()
    {
        char *a = {"p", "r", "o", "g", "r", "a", "m"};
        printf("%s", a);
    }

No output

Compile-time error

Output will be p

Output will be program

4. What will be the output of the following C code?

    #include <stdio.h>
    void main()
    {
        char *a[10] = {"hi", "hello", "how"};
        int i = 0, j = 0;
        a[0] = "hey";
        for (i = 0;i < 10; i++)
        printf("%s\n", a[i]);
    }

hi hello how Segmentation fault

depends on compiler

hi hello how followed by 7 null values

hey hello how Segmentation fault

5. What will be the output of the following C code on a 32-bit system?

    #include <stdio.h>
    void main()
    {
        char *a[10] = {"hi", "hello", "how"};
        printf("%d\n", sizeof(a));
    }

Run time error

6. What will be the output of the following C code?

    #include <stdio.h>
    void main()
    {
        char *a[10] = {"hi", "hello", "how"};
        int i = 0;
        for (i = 0;i < 10; i++)
        printf("%s", a[i]);
    }

hi hello how null

hi hello how Segmentation fault

hey hello how Segmentation fault

hi hello how followed by 7 nulls

7. Which of the following is the correct syntax to declare a 3 dimensional array using pointers?

char *a[][];

char ***a;

all of the mentioned

char **a[];

8. What will be the output of the following C code on a 32-bit system?

    #include <stdio.h>
    void main()
    {
        char *a[10] = {"hi", "hello", "how"};
        printf("%d\n", sizeof(a[1]));
    }